$newDt = Date.AddYear
("<date>", <n>)
Adds or subtracts n years to the given date.
Parameters
<date> Any valid date expression in dd/mm/yyyy format.
<n> Number of years as a positive or negative integer.
Return Value
Example
$sdate = "20/11/2005"
$ret = date.AddYear ($sdate, -5)
- $ret contains 20/11/2000.